28m^2-46m+14=8

Solution for 28m^2-46m+14=8 equation:

28m^2-46m+14=8

We move all terms to the left:

28m^2-46m+14-(8)=0

We add all the numbers together, and all the variables

28m^2-46m+6=0

a = 28; b = -46; c = +6;
Δ = b2-4ac
Δ = -462-4·28·6
Δ = 1444
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1444}=38$
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-46)-38}{2*28}=\frac{8}{56}
=1/7
$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-46)+38}{2*28}=\frac{84}{56}
=1+1/2
$